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on 2007-12-14 01:46 am (UTC)I have:
<CDE + <DEC = 160° <DEC + <AED = 150° <AED + <EDB = 130° <EDB + <CDE = 140° At this point, I realized that there must be some relationship, probably involving triangle ACB being isosceles, that I'm unaware of. The next rabbit hole I'm tempted to run down involved bisecting <DBE to get point F, with FE parallel to BA, and see if that gives me any more promising relationships. It does... It gives me an upper bound x < 70°